Elimination method (addition/subtraction)

LVL: FREE

MODULE: Equations and Inequalities

[EXEC: MICRO_CORE]

βœ–οΈ 1. Aligning equations cleanly in standard form (Ax+By=CAx + By = C)

πŸ“ Aligning Equations in Standard Form

  • Standard form means writing each equation as Ax+By=CAx + By = C.
  • Move all variable terms to the left side and constants to the right.
  • Stack equations vertically so like terms align in columns.
  • Both equations must use the same variable order (x first, then y).
  • This setup makes it easy to spot which variable to eliminate.

Example: Rewrite 3x=7βˆ’2y3x = 7 - 2y as 3x+2y=73x + 2y = 7, then stack with 5xβˆ’2y=15x - 2y = 1.

πŸ’‘ Think vertical columns: x-terms above x-terms, y-terms above y-terms!

[EXEC: DEEP_COMPUTE]

1. Aligning equations cleanly in standard form (Ax+By=CAx + By = C)

Aligning Equations in Standard Form

Before applying elimination, both equations must be written in standard form Ax+By=CAx + By = C, where AA, BB, and CC are constants and variables appear on the left side only. This alignment ensures that like terms (coefficients of xx and yy) are vertically positioned for direct comparison and manipulation.

Intuition: Organizing equations into columns makes it visually clear which coefficients can be targeted for elimination.

Core Rules:

  • Move all variable terms to the left side using inverse operations
  • Place the constant term alone on the right side
  • Arrange terms in consistent order (xx before yy)
  • Ensure coefficients are integers when possible (multiply through by denominators if needed)

Consequence: Proper alignment is the foundation for identifying which variable to eliminate and what multipliers are needed.

Example: Convert 3x=2y+73x = 2y + 7 to standard form: subtract 2y2y from both sides to get 3xβˆ’2y=73x - 2y = 7.

TASK_1[0 / 3]
LVL_2
STRC: TRANSFORM

Convert the equation 5x=4yβˆ’35x = 4y - 3 into standard form.

DEEP_COMPUTE
ULTRA
[EXEC: MICRO_CORE]

βœ–οΈ 2. Multiplying one or both equations by constants to create opposite coefficients

βœ–οΈ Creating Opposite Coefficients

  • Goal: Make one variable's coefficients opposites (like 3y3y and βˆ’3y-3y).
  • Multiply entire equations by constants to match absolute values.
  • If coefficients are already opposites, skip this step.
  • Multiply both sides of an equation to keep it balanced.
  • Sometimes multiply both equations by different numbers.

Example: To eliminate y from 2x+3y=82x + 3y = 8 and xβˆ’2y=5x - 2y = 5, multiply first by 2 and second by 3 to get 6y6y and βˆ’6y-6y.

πŸ’‘ Find the LCM of coefficients to know what multipliers you need!

[EXEC: DEEP_COMPUTE]

2. Multiplying one or both equations by constants to create opposite coefficients

Creating Opposite Coefficients Through Strategic Multiplication

To eliminate a variable, we multiply one or both equations by carefully chosen constants so that one variable has opposite coefficients (e.g., 3x3x and βˆ’3x-3x). When equations are added, these terms cancel completely.

Intuition: Scaling equations preserves their solutions while engineering coefficients that will annihilate each other upon addition.

Core Rules:

  • Identify the target variable for elimination
  • Find the least common multiple (LCM) of the coefficients if multiplying both equations
  • Multiply every term in the equation by the chosen constant
  • Make one coefficient positive and the other negative (or both negative if subtracting)

Consequence: This step transforms the system into a form where addition or subtraction directly removes one variable.

Example: Given 2x+3y=82x + 3y = 8 and xβˆ’y=1x - y = 1, multiply the second by βˆ’2-2 to get βˆ’2x+2y=βˆ’2-2x + 2y = -2, creating opposite xx-coefficients.

TASK_1[0 / 3]
LVL_2
EXEC: ALGORITHM

Given the following system of equations: Equation 1: 3x+4y=103x + 4y = 10 Equation 2: xβˆ’2y=3x - 2y = 3

To eliminate xx by adding the equations together, what number should you multiply Equation 2 by?

DEEP_COMPUTE
ULTRA
[EXEC: MICRO_CORE]

βœ–οΈ 3. Adding or subtracting equations to completely eliminate a variable

βž• Adding or Subtracting to Eliminate

  • Add equations when coefficients are opposites (one positive, one negative).
  • Subtract equations when coefficients are identical (both positive or both negative).
  • The chosen variable disappears completely after combining.
  • You get a single-variable equation to solve immediately.
  • Substitute the result back into either original equation to find the other variable.

Example: Add 4x+3y=104x + 3y = 10 and 4xβˆ’3y=64x - 3y = 6 to get 8x=168x = 16, so x=2x = 2.

πŸ’‘ Opposite signs? Add. Same signs? Subtract.

[EXEC: DEEP_COMPUTE]

3. Adding or subtracting equations to completely eliminate a variable

Eliminating a Variable Through Equation Combination

Once opposite coefficients are established, add the equations term-by-term to eliminate the target variable. If coefficients are identical (not opposite), subtract one equation from the other instead.

Intuition: Combining equations exploits the transitive property of equalityβ€”if A=BA = B and C=DC = D, then A+C=B+DA + C = B + D.

Core Rules:

  • Add equations when coefficients are opposites (e.g., 5x5x and βˆ’5x-5x)
  • Subtract equations when coefficients are identical (e.g., both 4y4y)
  • The eliminated variable's coefficient becomes zero
  • Solve the resulting single-variable equation immediately

Consequence: Elimination reduces a two-variable system to one equation in one unknown, which is directly solvable. Substitute back to find the second variable.

Example: Adding 3x+2y=113x + 2y = 11 and βˆ’3x+y=1-3x + y = 1 yields 3y=123y = 12, so y=4y = 4.

TASK_1[0 / 3]
LVL_2
EXEC: ALGORITHM

Given the system of equations: 2x+3y=102x + 3y = 10 βˆ’2x+y=6-2x + y = 6

Add the equations to eliminate xx, then find the value of yy.

DEEP_COMPUTE
ULTRA
[EXEC: MICRO_CORE]

βœ–οΈ 4. Comparing substitution vs. elimination to choose the most efficient solving strategy

βš–οΈ Substitution vs Elimination Strategy

  • Use substitution when one variable is already isolated (like y=3xβˆ’1y = 3x - 1).
  • Use elimination when coefficients are easy to match or already close.
  • Elimination avoids messy fractions when coefficients are whole numbers.
  • Substitution is faster for simple systems with one easy equation.
  • Check coefficients first: if they match or are opposites, elimination wins.

Example: For x+y=5x + y = 5 and xβˆ’y=1x - y = 1, elimination is instant (add to get 2x=62x = 6). For y=2xy = 2x and 3x+y=103x + y = 10, substitution is cleaner.

πŸ’‘ Isolated variable? Substitute. Matching coefficients? Eliminate.

[EXEC: DEEP_COMPUTE]

4. Comparing substitution vs. elimination to choose the most efficient solving strategy

Strategic Method Selection: Substitution vs. Elimination

Substitution isolates one variable and replaces it in the other equation, while elimination combines equations to cancel a variable. The optimal choice depends on the system's structure.

Intuition: Choose the method that minimizes algebraic complexity and computational steps.

Core Rules:

  • Use substitution when one variable is already isolated (e.g., y=2x+3y = 2x + 3) or has coefficient Β±1\pm 1
  • Use elimination when coefficients are easily manipulated to opposites or when both equations are in standard form
  • Avoid substitution if isolation creates fractions or complex expressions
  • Elimination is often faster for systems with integer coefficients

Consequence: Method selection impacts efficiency but not the solution itselfβ€”both yield identical results when applied correctly.

Example: For x+y=5x + y = 5 and 2xβˆ’y=42x - y = 4, elimination (add directly) is faster than isolating y=5βˆ’xy = 5 - x and substituting.

TASK_1[0 / 3]
LVL_2
ADV: STRATEGY

Given the system of equations: Equation 1: y=4xβˆ’1y = 4x - 1 Equation 2: 3x+2y=123x + 2y = 12

Based on the core rules for strategic method selection, which statement describes the optimal first step?

DEEP_COMPUTE
ULTRA
[EXEC: MICRO_CORE]

βœ–οΈ 5. Applications: Solving complex circuit loops using Kirchhoff's laws in physics

⚑ Circuit Loops with Kirchhoff's Laws

  • Kirchhoff's Voltage Law creates one equation per loop in a circuit.
  • Each loop equation relates currents using resistances and voltage sources.
  • Multiple loops give a system of equations with currents as variables.
  • Elimination solves for unknown currents flowing through branches.
  • This method handles complex circuits with multiple power sources.

Example: Loop 1 gives 5I1βˆ’3I2=125I_1 - 3I_2 = 12 and Loop 2 gives βˆ’3I1+8I2=6-3I_1 + 8I_2 = 6. Eliminate to find I1I_1 and I2I_2 in amperes.

πŸ’‘ Each loop = one equation; solve the system to find all currents!

[EXEC: DEEP_COMPUTE]

5. Applications: Solving complex circuit loops using Kirchhoff's laws in physics

Circuit Analysis with Kirchhoff's Laws

Kirchhoff's Voltage Law (KVL) states that the sum of voltage drops around any closed loop equals zero, generating linear equations in branch currents. Kirchhoff's Current Law (KCL) ensures current conservation at nodes. Multi-loop circuits produce systems solvable by elimination.

Intuition: Each loop equation relates currents through resistors; elimination isolates individual branch currents.

Core Rules:

  • Write one KVL equation per independent loop (voltage drops sum to zero)
  • Apply Ohm's law (V=IRV = IR) to express voltages in terms of currents
  • Use elimination to solve for unknown currents when loops share branches
  • Verify solutions satisfy both KVL and KCL

Consequence: Elimination handles the interdependence of loop currents systematically, essential for circuits with multiple power sources.

Example: Two loops sharing a resistor yield equations 5I1βˆ’2I2=105I_1 - 2I_2 = 10 and βˆ’2I1+8I2=6-2I_1 + 8I_2 = 6; elimination finds I1I_1 and I2I_2.

TASK_1[0 / 3]
LVL_2
EXEC: ALGORITHM

A circuit with two loops yields the following Kirchhoff's Voltage Law equations: Loop 1: 3I1+I2=103I_1 + I_2 = 10 Loop 2: I1βˆ’I2=2I_1 - I_2 = 2

Use elimination to find the value of the current I1I_1.

DEEP_COMPUTE
ULTRA

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