Expanding brackets

LVL: FREE

MODULE: Equations and Inequalities

[EXEC: MICRO_CORE]

✖️ 1. Applying the distributive property over addition and subtraction

📦 Distributive Property Over Addition and Subtraction

  • Multiply the outside term by every term inside the brackets.
  • For a(b+c)a(b + c), you get ab+acab + ac.
  • For a(bc)a(b - c), you get abacab - ac.
  • The operation inside the brackets stays the same in your answer.
  • Works with any numbers: whole numbers, fractions, or variables.

Example: 3(x+5)=3x+153(x + 5) = 3x + 15 and 4(y2)=4y84(y - 2) = 4y - 8

💡 Think: distribute means "share with everyone inside."

[EXEC: DEEP_COMPUTE]

1. Applying the distributive property over addition and subtraction

Applying the Distributive Property Over Addition and Subtraction

The distributive property states that multiplying a term by a sum (or difference) equals the sum (or difference) of the products: a(b+c)=ab+aca(b + c) = ab + ac and a(bc)=abaca(b - c) = ab - ac. This property allows us to "expand" or remove brackets by distributing the outer term to each term inside.

Intuition: Think of aa groups, each containing (b+c)(b + c) items. The total is the same whether you count all items at once or count bb items per group plus cc items per group separately.

Core Rules:

  • Multiply the term outside the bracket by every term inside the bracket.
  • Preserve the operation signs (+ or −) between terms inside the bracket.
  • Apply the property to both addition and subtraction: a(bc)=abaca(b - c) = ab - ac.
  • The order of multiplication does not matter: (b+c)a=ba+ca(b + c)a = ba + ca.

Consequence: Expanding brackets transforms expressions into equivalent forms without parentheses, enabling simplification and equation solving.

Example: 3(x+4)=3x+123(x + 4) = 3x + 12 and 5(2y3)=10y155(2y - 3) = 10y - 15.

TASK_1[0 / 3]
LVL_2
EXEC: ALGORITHM

Expand the expression using the distributive property: 4(x+5)4(x + 5).

DEEP_COMPUTE
ULTRA
[EXEC: MICRO_CORE]

✖️ 2. Managing negative signs correctly when expanding brackets

⚠️ Managing Negative Signs When Expanding

  • A negative outside the brackets flips every sign inside.
  • For a(b+c)-a(b + c), you get abac-ab - ac.
  • For a(bc)-a(b - c), you get ab+ac-ab + ac.
  • Negative times positive gives negative.
  • Negative times negative gives positive.

Example: 2(x+3)=2x6-2(x + 3) = -2x - 6 and 5(y4)=5y+20-5(y - 4) = -5y + 20

💡 Negative outside = flip all signs inside.

[EXEC: DEEP_COMPUTE]

2. Managing negative signs correctly when expanding brackets

Managing Negative Signs Correctly When Expanding Brackets

When a negative sign or negative coefficient precedes a bracket, it must be distributed to every term inside, reversing the sign of each term. The expression a(b+c)-a(b + c) becomes abac-ab - ac, not ab+ac-ab + ac.

Intuition: A negative outside the bracket acts like multiplying by 1-1, flipping the sign of each term inside. Forgetting this causes the most common expansion errors.

Core Rules:

  • Distribute the negative: (b+c)=bc-(b + c) = -b - c and (bc)=b+c-(b - c) = -b + c.
  • Negative coefficient: a(b+c)=abac-a(b + c) = -ab - ac.
  • Double negatives become positive: a(b)=ab-a(-b) = ab.
  • Always track sign changes term-by-term to avoid errors.

Consequence: Correct sign management is essential; a single sign error invalidates the entire expansion and any subsequent algebraic work.

Example: 2(x5)=2x+10-2(x - 5) = -2x + 10 (the 5-5 becomes +10+10 because 2×5=10-2 \times -5 = 10).

TASK_1[0 / 3]
LVL_2
EXEC: ALGORITHM

Expand the expression: (x+4)-(x + 4)

DEEP_COMPUTE
ULTRA
[EXEC: MICRO_CORE]

✖️ 3. Expanding nested brackets from the inside out

🎯 Expanding Nested Brackets

  • Always start with the innermost brackets first.
  • Expand from inside to outside, one layer at a time.
  • After expanding inner brackets, treat the result as a new expression.
  • Then expand the next outer layer using the distributive property.
  • Combine like terms at the very end.

Example: 2(3(x+1)+4)=2(3x+3+4)=2(3x+7)=6x+142(3(x + 1) + 4) = 2(3x + 3 + 4) = 2(3x + 7) = 6x + 14

💡 Think: peel the onion from the center outward.

[EXEC: DEEP_COMPUTE]

3. Expanding nested brackets from the inside out

Expanding Nested Brackets From the Inside Out

When brackets appear within other brackets (nested structure), expand systematically by working from the innermost bracket outward. This ensures each layer is simplified before addressing the next.

Intuition: Like unpacking nested boxes, you must open the innermost box first before you can access and open the outer layers. Skipping steps leads to errors.

Core Rules:

  • Identify the innermost bracket and expand it first.
  • Simplify the result by combining like terms if possible.
  • Move outward to the next bracket layer and repeat.
  • Maintain careful tracking of negative signs at each expansion step.

Consequence: This inside-out strategy prevents confusion and ensures all terms are correctly distributed across multiple layers of operations.

Example: 2[3(x+1)4]2[3(x + 1) - 4]. First expand inner: 3(x+1)=3x+33(x + 1) = 3x + 3, giving 2[3x+34]=2[3x1]2[3x + 3 - 4] = 2[3x - 1]. Then expand outer: 2(3x1)=6x22(3x - 1) = 6x - 2.

TASK_1[0 / 3]
LVL_2
EXEC: ALGORITHM

Expand and simplify the expression: 3[2(x+4)5]3[2(x + 4) - 5].

DEEP_COMPUTE
ULTRA
[EXEC: MICRO_CORE]

✖️ 4. Applications: Expressing the total area of partitioned spaces in architecture

🏛️ Applications in Architecture

  • Architects divide large spaces into smaller sections to calculate total area.
  • Use brackets to represent partitioned dimensions.
  • Expanding brackets gives the total area as a sum of parts.
  • For a room with width ww and sections of length aa and bb: w(a+b)=wa+wbw(a + b) = wa + wb.
  • Helps verify that sum of parts equals the whole.

Example: Room width 5 m, sections 3 m and 2 m: 5(3+2)=15+10=255(3 + 2) = 15 + 10 = 25 square meters

💡 Total area = sum of all partition areas.

[EXEC: DEEP_COMPUTE]

4. Applications: Expressing the total area of partitioned spaces in architecture

Applications: Expressing the Total Area of Partitioned Spaces in Architecture

In architectural design, spaces are often divided into rectangular sections. The total area can be expressed using the distributive property by treating one dimension as shared and the other as partitioned.

Intuition: A room of width ww divided into sections of lengths aa and bb has total area w(a+b)=wa+wbw(a + b) = wa + wb, representing the sum of individual section areas.

Core Rules:

  • Identify the shared dimension (constant width or height).
  • Express partitioned dimension as a sum of segment lengths.
  • Apply distributive property: Total area = (shared dimension) × (sum of segments).
  • Expanding gives the sum of individual areas, useful for material estimation and cost calculation.

Consequence: This method simplifies area calculations for complex floor plans and enables architects to compute material needs for each partition separately.

Example: A hallway 3 meters wide with sections 5 m and 7 m long has area 3(5+7)=15+21=363(5 + 7) = 15 + 21 = 36 square meters.

TASK_1[0 / 3]
LVL_2
EXEC: ALGORITHM

An architect is designing a rectangular room with a constant width of 44 meters. The room is divided into two sections with lengths of xx meters and 66 meters. Which expression represents the total area of the room using the distributive property before expanding?

DEEP_COMPUTE
ULTRA

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