Word problems leading to linear equations

LVL: FREE

MODULE: Equations and Inequalities

[EXEC: MICRO_CORE]

✖️ 1. Strictly defining the unknown variable and setting up the core equation

🎯 Defining the Unknown and Setting Up the Equation

  • Choose one unknown to represent with a variable (usually xx).
  • Read the problem and identify what quantity you need to find.
  • Translate the word relationship into an equation using ==.
  • Write units next to your variable to avoid confusion (e.g., xx books).
  • Check that both sides of the equation measure the same thing.

Example: "A number increased by 7 equals 15" becomes x+7=15x + 7 = 15.

💡 Let xx be the thing you're hunting for, then build the equation around it.

[EXEC: DEEP_COMPUTE]

1. Strictly defining the unknown variable and setting up the core equation

Strictly Defining the Unknown Variable and Setting Up the Core Equation

A variable is a symbol (typically xx, yy, or tt) representing an unknown quantity we aim to determine. The first step in translating a word problem into mathematics is to explicitly declare what the variable represents with units and context.

Intuition: Choosing the right unknown simplifies the equation. If the problem asks for "the number," let xx be that number directly, not a related quantity.

Core Rules:

  • Declare the variable precisely: Write "Let xx = [description with units]" before forming any equation.
  • Translate relationships into algebraic expressions: Keywords like "more than" (++), "less than" (-), "times" (×\times), "is/equals" (==) map directly to operations.
  • One equation per independent relationship: Each sentence describing a constraint typically yields one equation.
  • Check dimensional consistency: Both sides of the equation must have the same units.

Consequence: A well-defined variable and correctly structured equation guarantee that the solution directly answers the question.

Example: "A number increased by 7 equals 15." Let xx = the number. Equation: x+7=15x + 7 = 15. Solution: x=8x = 8.

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LVL_2
MOD: TRANSLATE

A word problem states: 'A number decreased by 12 equals 35.'

Let xx be the unknown number. Which equation correctly represents this relationship?

DEEP_COMPUTE
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[EXEC: MICRO_CORE]

✖️ 2. Solving number and consecutive integer relationship problems

🔢 Number and Consecutive Integer Problems

  • Consecutive integers are xx, x+1x+1, x+2x+2, etc.
  • Consecutive even or odd integers are xx, x+2x+2, x+4x+4, etc.
  • Sum or difference relationships translate directly into addition or subtraction.
  • "Twice a number" means 2x2x, "three less than" means x3x - 3.
  • Solve the equation and check if your answer makes sense in context.

Example: Three consecutive integers sum to 24 gives x+(x+1)+(x+2)=24x + (x+1) + (x+2) = 24, so 3x+3=243x + 3 = 24 and x=7x = 7.

💡 Consecutive means "add 1 each time" (or 2 for even/odd).

[EXEC: DEEP_COMPUTE]

2. Solving number and consecutive integer relationship problems

Solving Number and Consecutive Integer Relationship Problems

Consecutive integers are integers that follow one another in order, differing by 1. If nn is an integer, the next consecutive integer is n+1n+1, and the one after is n+2n+2.

Intuition: Represent the smallest or first integer as xx, then express all others in terms of xx using addition.

Core Rules:

  • Consecutive integers: xx, x+1x+1, x+2x+2, ...
  • Consecutive even integers: xx, x+2x+2, x+4x+4, ... (where xx is even).
  • Consecutive odd integers: xx, x+2x+2, x+4x+4, ... (where xx is odd).
  • Sum or product relationships: Translate "the sum of three consecutive integers is 48" into x+(x+1)+(x+2)=48x + (x+1) + (x+2) = 48.

Consequence: This systematic representation converts verbal constraints into solvable linear equations.

Example: Find three consecutive integers whose sum is 48. Let xx = first integer. Equation: x+(x+1)+(x+2)=48    3x+3=48    x=15x + (x+1) + (x+2) = 48 \implies 3x + 3 = 48 \implies x = 15. Integers: 15, 16, 17.

TASK_1[0 / 3]
LVL_2
MOD: TRANSLATEMOD: VARIABLES

Write the algebraic expression for the sum of three consecutive integers, starting with xx as the smallest integer.

Simplify your expression completely.

DEEP_COMPUTE
ULTRA
[EXEC: MICRO_CORE]

✖️ 3. Distance, rate, and time (kinematics) modeling

🚗 Distance, Rate, and Time Modeling

  • The core formula is distance = rate × time or d=rtd = rt.
  • Identify which quantity is unknown and solve for it.
  • For two objects, set up separate d=rtd = rt equations and relate them.
  • "Catch-up" problems use equal distances, "opposite directions" add distances.
  • Always check units (miles per hour with hours gives miles).

Example: A car travels 60 miles at 30 mph, so 60=30t60 = 30t gives t=2t = 2 hours.

💡 Draw a timeline or number line to visualize who moves where.

[EXEC: DEEP_COMPUTE]

3. Distance, rate, and time (kinematics) modeling

Distance, Rate, and Time (Kinematics) Modeling

The fundamental kinematic relationship is d=rtd = rt, where dd is distance traveled, rr is constant rate (speed), and tt is time elapsed.

Intuition: If two objects move, their distances, rates, or times relate through this formula. Identify which quantity is unknown and which are given or expressible in terms of a variable.

Core Rules:

  • Single motion: Use d=rtd = rt directly.
  • Opposite directions (separation): Total distance = r1t+r2tr_1 t + r_2 t if starting from the same point.
  • Same direction (catch-up): Distance difference = (rfastrslow)t(r_{\text{fast}} - r_{\text{slow}}) t.
  • Round trips or segments: Sum distances for each leg, ensuring time consistency.

Consequence: Most motion problems reduce to solving one linear equation in tt, rr, or dd.

Example: Two cars leave a city in opposite directions at 60 km/h and 80 km/h. When are they 420 km apart? Let tt = time in hours. Equation: 60t+80t=420    140t=420    t=360t + 80t = 420 \implies 140t = 420 \implies t = 3 hours.

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LVL_2
MOD: TRANSLATE

Two hikers leave a camp in opposite directions. The first hiker walks at 3 miles per hour, and the second hiker walks at 4 miles per hour. How many hours will it take for them to be 21 miles apart?

DEEP_COMPUTE
ULTRA
[EXEC: MICRO_CORE]

✖️ 4. Mixture, work-rate, and concentration problem archetypes

🧪 Mixture, Work-Rate, and Concentration Archetypes

  • Mixture problems: Total amount = sum of parts (e.g., xx liters of A plus yy liters of B).
  • Work-rate: If one person does a job in aa hours, their rate is 1a\frac{1}{a} jobs per hour.
  • Concentration: Amount of substance = concentration × total volume.
  • Combine rates or concentrations by adding contributions.
  • Set up one equation balancing total input and total output.

Example: Mixing 2 liters of 10% acid with 3 liters of 20% acid gives total acid =0.1(2)+0.2(3)=0.8= 0.1(2) + 0.2(3) = 0.8 liters.

💡 Think "part + part = whole" for mixtures and rates.

[EXEC: DEEP_COMPUTE]

4. Mixture, work-rate, and concentration problem archetypes

Mixture, Work-Rate, and Concentration Problem Archetypes

Mixture problems involve combining substances with different properties (concentration, price, purity). Work-rate problems model tasks completed at constant rates. Both use the principle: total = rate × amount.

Intuition: Track the quantity of interest (pure substance, work done) separately from the total volume or time.

Core Rules:

  • Mixture (concentration): Amount of pure substance = concentration × total volume. Equation: c1V1+c2V2=cfinalVfinalc_1 V_1 + c_2 V_2 = c_{\text{final}} V_{\text{final}}.
  • Mixture (value): Total value = price per unit × quantity.
  • Work-rate: If a task takes tt hours, the rate is 1t\frac{1}{t} tasks per hour. Combined rate: 1t1+1t2\frac{1}{t_1} + \frac{1}{t_2}.
  • Conservation: Total input equals total output.

Consequence: These problems require careful accounting of two quantities simultaneously (e.g., volume and concentration).

Example: Mix 2 L of 30% acid with xx L of 60% acid to get 45% acid. Equation: 0.30(2)+0.60x=0.45(2+x)    x=20.30(2) + 0.60x = 0.45(2+x) \implies x = 2 L.

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LVL_3
MOD: TRANSLATEMOD: VARIABLES

If a task takes 4 hours for one machine to complete and 12 hours for another machine to complete, how many hours does it take them to complete the task working together?

DEEP_COMPUTE
ULTRA
[EXEC: MICRO_CORE]

✖️ 5. Applications: Calculating final solution concentrations in chemistry and relative velocities in physics

⚗️ Final Concentrations and Relative Velocities

  • Final concentration = (total solute) ÷ (total solution volume).
  • For chemistry, track grams or moles of solute separately from total liters.
  • Relative velocity in physics = difference of velocities if same direction, sum if opposite.
  • Use vrel=v1v2v_{\text{rel}} = v_1 - v_2 (same direction) or vrel=v1+v2v_{\text{rel}} = v_1 + v_2 (opposite).
  • Plug relative velocity into d=rtd = rt to find meeting time or separation.

Example: 100 mL of 5% salt plus 200 mL of 10% salt gives final concentration =5+20300=8.33%= \frac{5 + 20}{300} = 8.33\%.

💡 Add the "stuff" (solute or speeds), then divide by total volume or use in d=rtd=rt.

[EXEC: DEEP_COMPUTE]

5. Applications: Calculating final solution concentrations in chemistry and relative velocities in physics

Applications: Calculating Final Solution Concentrations in Chemistry and Relative Velocities in Physics

Final concentration after mixing solutions is the ratio of total solute mass to total solution volume. Relative velocity is the velocity of one object as observed from another moving object.

Intuition: Concentration problems extend mixture archetypes; relative velocity problems simplify multi-object motion by choosing a moving reference frame.

Core Rules:

  • Concentration: cfinal=m1c1+m2c2m1+m2c_{\text{final}} = \frac{m_1 c_1 + m_2 c_2}{m_1 + m_2} (mass-weighted average). Solve for unknown mass or concentration.
  • Relative velocity (same direction): vrel=v1v2v_{\text{rel}} = v_1 - v_2.
  • Relative velocity (opposite directions): vrel=v1+v2v_{\text{rel}} = v_1 + v_2.
  • Application context: Chemistry uses molarity (mol/L); physics uses m/s or km/h.

Consequence: These specialized forms allow direct modeling of real-world scenarios in science and engineering.

Example: A 5% saline solution (200 mL) is mixed with a 15% solution (xx mL) to yield 10% concentration. Equation: 0.05(200)+0.15x=0.10(200+x)    x=2000.05(200) + 0.15x = 0.10(200+x) \implies x = 200 mL.

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LVL_2
MOD: TRANSLATE

Two trains are traveling in opposite directions. Train A has a velocity of 90 km/h and Train B has a velocity of 60 km/h. Calculate their relative velocity in km/h.

DEEP_COMPUTE
ULTRA

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