Even and odd functions (symmetry)

LVL: FREE

MODULE: Polynomials and Functions

✖️ 1. Algebraic tests for even functions f(x)=f(x)f(x) = f(-x) (yy-axis symmetry)

🪞 Algebraic Test for Even Functions

  • A function is even if f(x)=f(x)f(-x) = f(x) for all xx in the domain.
  • Even functions have y-axis symmetry (mirror image across the vertical axis).
  • To test: replace every xx with x-x and simplify.
  • If you get back the original function, it's even.
  • Common examples: f(x)=x2f(x) = x^2, f(x)=cos(x)f(x) = \cos(x), f(x)=xf(x) = |x|.

Test f(x)=x43x2f(x) = x^4 - 3x^2: compute f(x)=(x)43(x)2=x43x2=f(x)f(-x) = (-x)^4 - 3(-x)^2 = x^4 - 3x^2 = f(x), so it's even.

💡 Even = Mirror across y-axis = Same left and right

1. Algebraic tests for even functions f(x)=f(x)f(x) = f(-x) (yy-axis symmetry)

Algebraic Test for Even Functions

A function ff is even if and only if f(x)=f(x)f(-x) = f(x) for all xx in its domain. This condition means the function's graph is symmetric about the yy-axis.

Intuition: Replacing xx with x-x leaves the output unchanged, so points (x,y)(x, y) and (x,y)(-x, y) both lie on the graph.

Core Rules:

  • Test: Compute f(x)f(-x) and simplify completely. If the result equals f(x)f(x), the function is even.
  • Domain requirement: The domain must be symmetric about zero (if xx is in the domain, so is x-x).
  • Common examples: f(x)=x2f(x) = x^2, f(x)=cos(x)f(x) = \cos(x), f(x)=xf(x) = |x|.

Consequence: Even functions satisfy aaf(x)dx=20af(x)dx\int_{-a}^{a} f(x)\,dx = 2\int_{0}^{a} f(x)\,dx when the integral exists.

Example: For f(x)=3x45x2+7f(x) = 3x^4 - 5x^2 + 7, compute f(x)=3(x)45(x)2+7=3x45x2+7=f(x)f(-x) = 3(-x)^4 - 5(-x)^2 + 7 = 3x^4 - 5x^2 + 7 = f(x), so ff is even.

No practice tasks yet

We haven't added practice for this part of the topic yet. Keep reading — the rest of the topic still works.

✖️ 2. Algebraic tests for odd functions f(x)=f(x)f(-x) = -f(x) (origin symmetry)

🔄 Algebraic Test for Odd Functions

  • A function is odd if f(x)=f(x)f(-x) = -f(x) for all xx in the domain.
  • Odd functions have origin symmetry (rotate 180 degrees around the origin).
  • To test: replace every xx with x-x and simplify.
  • If you get the negative of the original, it's odd.
  • Common examples: f(x)=x3f(x) = x^3, f(x)=sin(x)f(x) = \sin(x), f(x)=xf(x) = x.

Test f(x)=2x5xf(x) = 2x^5 - x: compute f(x)=2(x)5(x)=2x5+x=(2x5x)=f(x)f(-x) = 2(-x)^5 - (-x) = -2x^5 + x = -(2x^5 - x) = -f(x), so it's odd.

💡 Odd = Spin 180° around origin = Opposite on both sides

2. Algebraic tests for odd functions f(x)=f(x)f(-x) = -f(x) (origin symmetry)

Algebraic Test for Odd Functions

A function ff is odd if and only if f(x)=f(x)f(-x) = -f(x) for all xx in its domain. This condition corresponds to rotational symmetry about the origin by 180 degrees.

Intuition: Replacing xx with x-x negates the output, so point (x,y)(x, y) on the graph implies (x,y)(-x, -y) is also on the graph.

Core Rules:

  • Test: Compute f(x)f(-x) and simplify. If the result equals f(x)-f(x), the function is odd.
  • Domain requirement: The domain must be symmetric about zero.
  • Common examples: f(x)=x3f(x) = x^3, f(x)=sin(x)f(x) = \sin(x), f(x)=1xf(x) = \frac{1}{x}.
  • Special property: If ff is odd and defined at zero, then f(0)=0f(0) = 0 (since f(0)=f(0)f(0) = -f(0) implies f(0)=0f(0) = 0).

Consequence: For odd functions, aaf(x)dx=0\int_{-a}^{a} f(x)\,dx = 0 when the integral exists.

Example: For f(x)=2x54xf(x) = 2x^5 - 4x, compute f(x)=2(x)54(x)=2x5+4x=(2x54x)=f(x)f(-x) = 2(-x)^5 - 4(-x) = -2x^5 + 4x = -(2x^5 - 4x) = -f(x), so ff is odd.

No practice tasks yet

We haven't added practice for this part of the topic yet. Keep reading — the rest of the topic still works.

✖️ 3. Determining parity of sums and products of even/odd functions

➕✖️ Parity of Sums and Products

  • Even + Even = Even, Odd + Odd = Odd, Even + Odd = Neither.
  • Even × Even = Even, Odd × Odd = Even, Even × Odd = Odd.
  • These rules work like algebra with signs.
  • Use them to quickly determine parity without full algebraic tests.

If g(x)=x2g(x) = x^2 (even) and h(x)=x3h(x) = x^3 (odd), then g(x)+h(x)=x2+x3g(x) + h(x) = x^2 + x^3 is neither, but g(x)h(x)=x5g(x) \cdot h(x) = x^5 is odd.

💡 Think: Even = +1, Odd = -1, then multiply/add those signs

3. Determining parity of sums and products of even/odd functions

Parity Rules for Combinations

The parity of sums and products of even and odd functions follows algebraic rules derived from their defining properties.

Intuition: Symmetry properties combine predictably: adding symmetric objects preserves symmetry type, while multiplication follows sign rules.

Core Rules:

  • Sum of two even functions is even: (f+g)(x)=f(x)+g(x)=f(x)+g(x)(f + g)(-x) = f(-x) + g(-x) = f(x) + g(x).
  • Sum of two odd functions is odd: (f+g)(x)=f(x)+g(x)=f(x)g(x)=(f+g)(x)(f + g)(-x) = f(-x) + g(-x) = -f(x) - g(x) = -(f + g)(x).
  • Product of two even functions is even: (fg)(x)=f(x)g(x)=f(x)g(x)(fg)(-x) = f(-x)g(-x) = f(x)g(x).
  • Product of two odd functions is even: (fg)(x)=f(x)g(x)=[f(x)][g(x)]=f(x)g(x)(fg)(-x) = f(-x)g(-x) = [-f(x)][-g(x)] = f(x)g(x).
  • Product of even and odd is odd: (fg)(x)=f(x)g(x)=f(x)[g(x)]=f(x)g(x)(fg)(-x) = f(-x)g(-x) = f(x)[-g(x)] = -f(x)g(x).

Consequence: These rules enable quick parity determination for composite functions without explicit computation.

Example: If f(x)=x2f(x) = x^2 (even) and g(x)=x3g(x) = x^3 (odd), then f(x)g(x)=x5f(x)g(x) = x^5 is odd.

No practice tasks yet

We haven't added practice for this part of the topic yet. Keep reading — the rest of the topic still works.

✖️ 4. Identifying functions that are neither even nor odd

🚫 Functions That Are Neither

  • Most functions are neither even nor odd.
  • If f(x)f(x)f(-x) \neq f(x) and f(x)f(x)f(-x) \neq -f(x), the function has no symmetry.
  • Test both conditions; if both fail, it's neither.
  • Example: f(x)=x2+xf(x) = x^2 + x fails both tests.

For f(x)=x2+3xf(x) = x^2 + 3x: compute f(x)=x23xf(-x) = x^2 - 3x, which is not f(x)f(x) and not f(x)=x23x-f(x) = -x^2 - 3x, so neither.

💡 No mirror, no spin = Neither

4. Identifying functions that are neither even nor odd

Functions with No Parity

A function is neither even nor odd if it fails both tests: f(x)f(x)f(-x) \neq f(x) and f(x)f(x)f(-x) \neq -f(x) for at least one xx in the domain.

Intuition: Most functions lack symmetry about the yy-axis or origin, exhibiting asymmetric behavior.

Core Rules:

  • Test both conditions: Compute f(x)f(-x) and compare to both f(x)f(x) and f(x)-f(x). If neither equality holds, the function has no parity.
  • Common examples: f(x)=x2+xf(x) = x^2 + x, f(x)=exf(x) = e^x, f(x)=2x+1f(x) = 2^x + 1.
  • Decomposition theorem: Any function with symmetric domain can be uniquely written as f(x)=feven(x)+fodd(x)f(x) = f_{\text{even}}(x) + f_{\text{odd}}(x) where feven(x)=f(x)+f(x)2f_{\text{even}}(x) = \frac{f(x) + f(-x)}{2} and fodd(x)=f(x)f(x)2f_{\text{odd}}(x) = \frac{f(x) - f(-x)}{2}.

Consequence: Recognizing lack of parity is essential before applying symmetry-based integration or analysis techniques.

Example: For f(x)=x2+3xf(x) = x^2 + 3x, compute f(x)=x23xf(-x) = x^2 - 3x. Since f(x)f(x)f(-x) \neq f(x) and f(x)f(x)f(-x) \neq -f(x), the function is neither even nor odd.

No practice tasks yet

We haven't added practice for this part of the topic yet. Keep reading — the rest of the topic still works.

✖️ 5. Applications: Analyzing harmonic signals and symmetric waves in acoustics or electromagnetics

🎵 Symmetry in Waves and Signals

  • Even functions (like cos\cos) represent symmetric waves with no phase shift.
  • Odd functions (like sin\sin) represent antisymmetric waves passing through the origin.
  • In Fourier analysis, even signals use only cosine terms, odd signals use only sine terms.
  • Symmetry simplifies calculations in acoustics, electromagnetics, and signal processing.
  • Recognizing parity reduces computation by half in many physics problems.

A vibrating string fixed at both ends has displacement y(x,t)=Asin(kx)cos(ωt)y(x,t) = A\sin(kx)\cos(\omega t), where sin(kx)\sin(kx) is odd in space.

💡 Even = Cosine waves, Odd = Sine waves

5. Applications: Analyzing harmonic signals and symmetric waves in acoustics or electromagnetics

Symmetry in Wave Analysis

Even and odd function properties simplify Fourier analysis of periodic signals in acoustics and electromagnetics. A signal's symmetry determines which frequency components (cosine or sine) appear in its spectrum.

Intuition: Even signals contain only cosine terms (symmetric waves), while odd signals contain only sine terms (antisymmetric waves), reducing computational complexity.

Core Rules:

  • Even signals: Fourier series contains only cosine terms and a constant: f(t)=a0+ancos(nωt)f(t) = a_0 + \sum a_n \cos(n\omega t).
  • Odd signals: Fourier series contains only sine terms: f(t)=bnsin(nωt)f(t) = \sum b_n \sin(n\omega t).
  • Half-wave symmetry: If f(t+T/2)=f(t)f(t + T/2) = -f(t), only odd harmonics appear.
  • Energy distribution: Symmetry determines power distribution across frequency bands.

Consequence: Identifying signal parity before Fourier decomposition halves the number of coefficients to compute, accelerating spectral analysis in signal processing.

Example: A square wave with f(t)=f(t)f(-t) = -f(t) (odd) has Fourier series f(t)=4πn=1,3,5,...sin(nωt)nf(t) = \frac{4}{\pi}\sum_{n=1,3,5,...} \frac{\sin(n\omega t)}{n}, containing only sine terms.

No practice tasks yet

We haven't added practice for this part of the topic yet. Keep reading — the rest of the topic still works.

Finished reading?

Mark this as read to track your progress.