Linear function and its graph (y=kx+by = kx + b)

LVL: FREE

MODULE: Polynomials and Functions

✖️ 1. Slope (kk) as rate of change and the yy-intercept (bb) as initial value

📐 Slope and Y-Intercept Decoded

  • Slope kk tells you how much yy changes when xx increases by 1.
  • Positive kk means the line goes upward; negative kk means downward.
  • Y-intercept bb is where the line crosses the yy-axis (when x=0x = 0).
  • In y=kx+by = kx + b, start at bb on the yy-axis, then use kk to find the next point.
  • If k=3k = 3, moving right 1 unit means moving up 3 units.

Example: y=2x+5y = 2x + 5 has slope 2 (rise 2 per 1 right) and starts at y=5y = 5.

💡 Think: kk is the steepness, bb is the launch point!

1. Slope (kk) as rate of change and the yy-intercept (bb) as initial value

Slope and yy-Intercept in Linear Functions

A linear function has the form y=kx+by = kx + b, where kk is the slope and bb is the yy-intercept. The slope kk measures the rate of change of yy with respect to xx, while bb represents the value of yy when x=0x = 0.

Intuitively, kk tells us how steep the line is and whether it rises or falls, and bb gives the starting point on the vertical axis.

Core Rules:

  • Slope k>0k > 0: line rises from left to right
  • Slope k<0k < 0: line falls from left to right
  • Slope k=0k = 0: horizontal line (constant function)
  • yy-intercept bb: the point (0,b)(0, b) where the line crosses the yy-axis

These parameters completely determine the line's position and orientation in the plane.

Example: In y=3x+2y = 3x + 2, the slope is 33 (for each unit increase in xx, yy increases by 33) and the yy-intercept is 22 (the line crosses the yy-axis at (0,2)(0, 2)).

Progress0 / 3
Level 2
STRC: TRANSFORM

Given the linear function y=4x+7y = -4x + 7, what is the slope and what does it tell us about the line?

Deep reasoning
Ultra
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✖️ 2. Graphing lines using the slope-intercept method

✏️ Graphing Lines Fast

  • Step 1: Plot the yy-intercept bb on the yy-axis.
  • Step 2: Use slope k=riserunk = \frac{\text{rise}}{\text{run}} to find a second point.
  • Move right by the run, then up or down by the rise.
  • Connect the two points with a straight line and extend it.
  • If kk is a fraction like 34\frac{3}{4}, rise 3 and run 4.

Example: For y=12x+3y = -\frac{1}{2}x + 3, plot (0,3)(0, 3), then go right 2 and down 1 to (2,2)(2, 2).

💡 Remember: Start at bb, then follow the slope like stairs!

2. Graphing lines using the slope-intercept method

Graphing Lines Using Slope-Intercept Method

The slope-intercept method uses the form y=kx+by = kx + b to graph a line by first plotting the yy-intercept, then using the slope to find additional points. This approach directly translates the equation's parameters into geometric steps.

Start at (0,b)(0, b) on the yy-axis, then move according to the slope k=riserunk = \frac{\text{rise}}{\text{run}}.

Core Rules:

  • Plot the yy-intercept: mark the point (0,b)(0, b)
  • Apply the slope: from (0,b)(0, b), move kk units vertically per 11 unit horizontally (or use k=mnk = \frac{m}{n} to move mm units up and nn units right)
  • Draw the line: connect the points and extend in both directions
  • Negative slope: move down instead of up

This method ensures accuracy and efficiency when sketching linear graphs.

Example: For y=2x+1y = -2x + 1, plot (0,1)(0, 1), then move down 22 units and right 11 unit to reach (1,1)(1, -1); draw the line through these points.

Progress0 / 3
Level 2
MOD: RELATE

If you start graphing the line y=3x+2y = 3x + 2 by plotting the y-intercept at (0,2)(0, 2), what will be the y-coordinate of the next point if you move exactly 11 unit to the right?

Deep reasoning
Ultra

✖️ 3. Determining equations of lines from graphs or two given points

🔍 Finding the Equation

  • From a graph: Read bb where the line crosses the yy-axis, then count rise over run for kk.
  • From two points: Calculate slope k=y2y1x2x1k = \frac{y_2 - y_1}{x_2 - x_1}, then plug one point into y=kx+by = kx + b to solve for bb.
  • Always simplify kk to lowest terms.
  • Check your equation by substituting both points back in.

Example: Points (1,4)(1, 4) and (3,10)(3, 10) give k=10431=3k = \frac{10 - 4}{3 - 1} = 3; using (1,4)(1, 4): 4=3(1)+bb=14 = 3(1) + b \Rightarrow b = 1, so y=3x+1y = 3x + 1.

💡 Shortcut: Slope first, then plug to find bb!

3. Determining equations of lines from graphs or two given points

Determining Equations from Graphs or Points

To find the equation y=kx+by = kx + b of a line, we need two pieces of information: the slope kk and the yy-intercept bb. These can be extracted from a graph or calculated from two points.

From a graph, read bb directly where the line crosses the yy-axis and compute kk using any two visible points. From two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2), calculate kk first, then solve for bb.

Core Rules:

  • Slope from two points: k=y2y1x2x1k = \frac{y_2 - y_1}{x_2 - x_1} (where x2x1x_2 \neq x_1)
  • Find bb: substitute one point and the slope into y=kx+by = kx + b and solve
  • From graph: identify intercept visually and use rise over run between grid points

This process uniquely determines the linear equation.

Example: Given points (1,3)(1, 3) and (4,9)(4, 9), slope k=9341=2k = \frac{9-3}{4-1} = 2; substituting (1,3)(1, 3): 3=2(1)+b3 = 2(1) + b gives b=1b = 1, so y=2x+1y = 2x + 1.

Progress0 / 3
Level 2
MOD: RELATE

A line passes through the points (2,5)(2, 5) and (4,11)(4, 11). Calculate the slope kk of this line.

Deep reasoning
Ultra

✖️ 4. Parallel and perpendicular lines: relationship between slopes

⚖️ Parallel and Perpendicular Lines

  • Parallel lines have identical slopes (k1=k2k_1 = k_2) but different yy-intercepts.
  • Perpendicular lines have slopes that are negative reciprocals (k1k2=1k_1 \cdot k_2 = -1).
  • If one slope is ab\frac{a}{b}, the perpendicular slope is ba-\frac{b}{a}.
  • Horizontal lines (k=0k = 0) are perpendicular to vertical lines (undefined slope).

Example: y=2x+1y = 2x + 1 is parallel to y=2x5y = 2x - 5; perpendicular to y=12x+3y = -\frac{1}{2}x + 3 since 2(12)=12 \cdot (-\frac{1}{2}) = -1.

💡 Visual: Parallel = same tilt; perpendicular = flip and negate!

4. Parallel and perpendicular lines: relationship between slopes

Parallel and Perpendicular Lines

Two non-vertical lines are parallel if they have equal slopes, and perpendicular if the product of their slopes equals 1-1. These slope relationships determine the geometric configuration of lines in the plane.

Parallel lines never intersect because they rise at the same rate; perpendicular lines intersect at right angles.

Core Rules:

  • Parallel lines: k1=k2k_1 = k_2 (same slope, different yy-intercepts)
  • Perpendicular lines: k1k2=1k_1 \cdot k_2 = -1, equivalently k2=1k1k_2 = -\frac{1}{k_1} (negative reciprocal)
  • Vertical and horizontal: a vertical line (undefined slope) is perpendicular to any horizontal line (slope 00)
  • Exception: vertical lines cannot be expressed in slope-intercept form

These conditions are both necessary and sufficient for the respective geometric relationships.

Example: Lines y=3x+1y = 3x + 1 and y=3x5y = 3x - 5 are parallel (both have slope 33); lines y=2x+1y = 2x + 1 and y=12x+4y = -\frac{1}{2}x + 4 are perpendicular since 2(12)=12 \cdot (-\frac{1}{2}) = -1.

Progress0 / 3
Level 2
MOD: RELATE

A line is given by the equation y=6x2y = 6x - 2. What is the slope of any line that is parallel to this line?

Deep reasoning
Ultra

✖️ 5. Applications: Modeling constant speed motion in physics or simple tax/utility bills in economics

🌍 Real-World Linear Models

  • Constant speed: Distance d=vt+d0d = vt + d_0 where vv is speed (slope) and d0d_0 is starting position.
  • Utility bills: Cost C=rt+fC = rt + f where rr is rate per unit (slope) and ff is fixed fee.
  • Tax calculations: Total T=px+bT = px + b where pp is tax rate and bb is base amount.
  • The slope always represents the rate of change per unit.
  • The yy-intercept is the starting value when input is zero.

Example: A taxi charges 3 dollars per km plus 5 dollars flat fee: C=3x+5C = 3x + 5 where xx is km traveled.

💡 Key: Slope = rate, intercept = starting point in any scenario!

5. Applications: Modeling constant speed motion in physics or simple tax/utility bills in economics

Applications of Linear Functions

Linear functions model situations where one quantity changes at a constant rate relative to another. In physics, constant speed motion follows d=vt+d0d = vt + d_0 (distance equals speed times time plus initial position). In economics, utility bills often have the form C=rq+fC = rq + f (total cost equals rate per unit times quantity plus fixed fee).

The slope represents the constant rate (speed, price per unit), and the yy-intercept represents the initial condition (starting position, base fee).

Core Rules:

  • Physics motion: kk is velocity (meters per second), bb is initial position
  • Economics billing: kk is unit rate (dollars per kilowatt-hour), bb is fixed charge
  • Interpretation: slope gives marginal change, intercept gives baseline value
  • Domain restrictions: often x0x \geq 0 in real applications

Linear models provide simple yet powerful tools for prediction and analysis.

Example: A taxi charges 3 dollars per kilometer plus a 5 dollar base fare; the cost function is C=3d+5C = 3d + 5, where dd is distance in kilometers.

Progress0 / 3
Level 2
MOD: TRANSLATE

A utility company charges a fixed fee of 15 dollars per month, plus 0.20 dollars for each kilowatt-hour used. If qq represents the kilowatt-hours used, what is the value of the yy-intercept in the linear function modeling the total cost?

Deep reasoning
Ultra

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