Right triangles and the Pythagorean Theorem

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MODULE: Planimetry (2D Geometry)

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✖️ 1. The Pythagorean Theorem: a2+b2=c2a^2 + b^2 = c^2

📐 The Pythagorean Theorem: a2+b2=c2a^2 + b^2 = c^2

  • In a right triangle, the two shorter sides are called legs (a and b).
  • The longest side opposite the right angle is the hypotenuse (c).
  • The theorem states: leg squared plus leg squared equals hypotenuse squared.
  • This formula ONLY works for right triangles (triangles with a 90-degree angle).
  • Always identify which side is the hypotenuse before applying the formula.

Example: If legs are 3 and 4, then 32+42=9+16=253^2 + 4^2 = 9 + 16 = 25, so c=5c = 5.

💡 The hypotenuse is always the longest side and sits across from the right angle.

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1. The Pythagorean Theorem: a2+b2=c2a^2 + b^2 = c^2

The Pythagorean Theorem: a2+b2=c2a^2 + b^2 = c^2

The Pythagorean Theorem states that in a right triangle, the square of the hypotenuse equals the sum of the squares of the two legs. Here, cc denotes the hypotenuse (the side opposite the right angle), and aa and bb denote the legs.

This relationship holds because the area of a square built on the hypotenuse equals the combined areas of squares built on the two legs.

Core Rules:

  • The theorem applies only to right triangles (triangles with exactly one 90-degree angle).
  • The hypotenuse cc is always the longest side.
  • The equation a2+b2=c2a^2 + b^2 = c^2 is symmetric in aa and bb (order of legs does not matter).
  • All three sides must be positive real numbers.

This theorem is foundational for distance calculations and geometric proofs.

Example: If a=3a = 3 and b=4b = 4, then c2=32+42=9+16=25c^2 = 3^2 + 4^2 = 9 + 16 = 25, so c=5c = 5.

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A right triangle has legs of length a=6a = 6 and b=8b = 8. Calculate the length of the hypotenuse cc.

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✖️ 2. Calculating the hypotenuse vs. a leg

🔍 Calculating the hypotenuse vs. a leg

  • Finding the hypotenuse: Add the squares of both legs, then take the square root.
  • Formula: c=a2+b2c = \sqrt{a^2 + b^2}.
  • Finding a missing leg: Subtract the known leg squared from the hypotenuse squared, then take the square root.
  • Formula: a=c2b2a = \sqrt{c^2 - b^2} or b=c2a2b = \sqrt{c^2 - a^2}.
  • Always check which side you are solving for before choosing the formula.

Example: If c=13c = 13 and a=5a = 5, then b=13252=16925=144=12b = \sqrt{13^2 - 5^2} = \sqrt{169 - 25} = \sqrt{144} = 12.

💡 Hypotenuse uses addition; missing leg uses subtraction.

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2. Calculating the hypotenuse vs. a leg

Calculating the Hypotenuse vs. a Leg

Given two sides of a right triangle, we use the Pythagorean Theorem to find the third side. The calculation differs depending on whether we seek the hypotenuse or a leg.

When finding the hypotenuse, we add the squares of the legs and take the square root. When finding a leg, we subtract the square of the known leg from the square of the hypotenuse, then take the square root.

Core Rules:

  • Finding hypotenuse: c=a2+b2c = \sqrt{a^2 + b^2} (given both legs aa and bb).
  • Finding a leg: a=c2b2a = \sqrt{c^2 - b^2} (given hypotenuse cc and one leg bb).
  • The value under the square root must be non-negative; otherwise, no real solution exists.
  • Always verify that the hypotenuse is the longest side.

These formulas enable solving for any unknown side when two sides are known.

Example: Given c=13c = 13 and b=5b = 5, then a=13252=16925=144=12a = \sqrt{13^2 - 5^2} = \sqrt{169 - 25} = \sqrt{144} = 12.

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A right triangle has two legs with lengths a=6a = 6 and b=8b = 8. Calculate the length of the hypotenuse cc.

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✖️ 3. Converse of the Pythagorean Theorem: verifying right triangles

✅ Converse of the Pythagorean Theorem: verifying right triangles

  • The converse lets you check if a triangle is a right triangle using side lengths.
  • Test: Does a2+b2=c2a^2 + b^2 = c^2 where c is the longest side?
  • If YES, the triangle is a right triangle.
  • If NO, the triangle is NOT a right triangle.
  • Always square the longest side separately and compare it to the sum of the other two squares.

Example: Sides 8, 15, 17. Check: 82+152=64+225=2898^2 + 15^2 = 64 + 225 = 289 and 172=28917^2 = 289. They match, so it IS a right triangle.

💡 If the equation balances, you have a right angle.

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3. Converse of the Pythagorean Theorem: verifying right triangles

Converse of the Pythagorean Theorem: Verifying Right Triangles

The converse of the Pythagorean Theorem states that if three positive numbers aa, bb, and cc satisfy a2+b2=c2a^2 + b^2 = c^2 (where cc is the largest), then they form the sides of a right triangle. This provides a test to verify whether a triangle is right-angled without measuring angles.

If the equation holds, the triangle has a right angle opposite the side of length cc.

Core Rules:

  • Test: Check if a2+b2=c2a^2 + b^2 = c^2 where cc is the longest side.
  • If a2+b2<c2a^2 + b^2 < c^2, the triangle is obtuse (angle opposite cc exceeds 90 degrees).
  • If a2+b2>c2a^2 + b^2 > c^2, the triangle is acute (all angles less than 90 degrees).
  • The converse requires exact equality; approximations may lead to incorrect conclusions.

This test is essential in geometry and construction to confirm perpendicularity.

Example: Sides 8, 15, 17 satisfy 82+152=64+225=289=1728^2 + 15^2 = 64 + 225 = 289 = 17^2, confirming a right triangle.

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A triangle has side lengths of 5, 12, and 13. Using the converse of the Pythagorean Theorem, classify this triangle.

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✖️ 4. Introduction to Pythagorean Triples (3-4-5, 5-12-13, etc.)

🎯 Introduction to Pythagorean Triples

  • A Pythagorean triple is a set of three whole numbers that satisfy a2+b2=c2a^2 + b^2 = c^2.
  • Common triples: 3-4-5, 5-12-13, 8-15-17, 7-24-25.
  • Any multiple of a triple is also a triple (e.g., 6-8-10 is double 3-4-5).
  • Recognizing triples saves time because you skip the square root calculation.
  • Triples always form right triangles with integer side lengths.

Example: If you see sides 9, 12, 15, recognize it as 3 times the 3-4-5 triple, so it is a right triangle.

💡 Memorize 3-4-5 and 5-12-13 to spot right triangles instantly.

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4. Introduction to Pythagorean Triples (3-4-5, 5-12-13, etc.)

Introduction to Pythagorean Triples

A Pythagorean triple is a set of three positive integers aa, bb, cc satisfying a2+b2=c2a^2 + b^2 = c^2. These triples represent the side lengths of right triangles with integer dimensions.

Common examples include (3, 4, 5) and (5, 12, 13). Any integer multiple of a Pythagorean triple is also a Pythagorean triple.

Core Rules:

  • A primitive triple has no common factor greater than 1 among aa, bb, cc (e.g., (3, 4, 5)).
  • Scaling: If (a,b,c)(a, b, c) is a triple, then (ka,kb,kc)(ka, kb, kc) is also a triple for any positive integer kk.
  • The smallest Pythagorean triple is (3, 4, 5).
  • Infinitely many Pythagorean triples exist.

Pythagorean triples simplify calculations in construction, navigation, and theoretical mathematics.

Example: (3, 4, 5) is primitive; scaling by 2 gives (6, 8, 10), which also satisfies 62+82=1026^2 + 8^2 = 10^2.

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Given the primitive Pythagorean triple (5, 12, 13), find the value of the hypotenuse if the entire triple is scaled by a factor of 3.

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✖️ 5. Applications: Calculating Euclidean distance in navigation and diagonal stress in structural frames

🌍 Applications: distance and structural stress

  • Euclidean distance between two points uses the Pythagorean theorem in coordinate geometry.
  • Formula: d=(x2x1)2+(y2y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} treats horizontal and vertical differences as legs.
  • Diagonal bracing in frames uses the theorem to calculate the length of support beams.
  • Engineers use it to find stress forces along diagonals in bridges and buildings.
  • Navigation systems calculate shortest paths by treating east-west and north-south as perpendicular legs.

Example: Points (1, 2) and (4, 6) have distance (41)2+(62)2=9+16=5\sqrt{(4-1)^2 + (6-2)^2} = \sqrt{9 + 16} = 5 units.

💡 Horizontal and vertical movements form the legs; straight-line distance is the hypotenuse.

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5. Applications: Calculating Euclidean distance in navigation and diagonal stress in structural frames

Applications: Euclidean Distance and Structural Stress

The Pythagorean Theorem extends beyond pure geometry to practical fields. In navigation, the straight-line distance between two points with horizontal and vertical separations forms the hypotenuse of a right triangle. In engineering, diagonal members in frames experience stress calculated using the theorem.

These applications rely on modeling real-world scenarios as right triangles.

Core Rules:

  • Euclidean distance: For points separated by horizontal distance xx and vertical distance yy, the direct distance is d=x2+y2d = \sqrt{x^2 + y^2}.
  • Structural diagonals: A rectangular frame with width ww and height hh has diagonal length w2+h2\sqrt{w^2 + h^2}.
  • Units must be consistent across all measurements.
  • The theorem assumes flat (Euclidean) geometry; it does not apply on curved surfaces.

These methods are foundational in GPS systems, architecture, and physics.

Example: A ship travels 30 km east and 40 km north; the direct distance is 302+402=900+1600=50\sqrt{30^2 + 40^2} = \sqrt{900 + 1600} = 50 km.

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A hiker walks 6 km east and 8 km north. What is the direct distance in km?

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