Exponential growth and decay

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MODULE: Pre-Calculus (Functions and Series)

✖️ 1. Explicitly distinguishing discrete vs. continuous growth/decay models

🔄 Discrete vs Continuous Models

  • Discrete growth uses a(1+r)ta(1+r)^t where tt counts whole steps (years, generations).
  • Continuous growth uses AertAe^{rt} where tt flows smoothly (any real number).
  • Use discrete when events happen at fixed intervals (annual interest).
  • Use continuous when change happens every instant (bacterial growth).
  • Both models give the same result at integer times if er=1+re^r = 1+r is satisfied.

A population starts at 100 and grows 5% yearly: discrete gives 100(1.05)3=115.76100(1.05)^3 = 115.76 after 3 years, continuous gives 100e0.048793115.76100e^{0.04879 \cdot 3} \approx 115.76.

💡 Discrete = steps, Continuous = flow.

1. Explicitly distinguishing discrete vs. continuous growth/decay models

Discrete vs. Continuous Exponential Models

Exponential processes occur in two fundamental forms: discrete models where changes happen at fixed intervals, and continuous models where change is instantaneous. The discrete model A(t)=a(1+r)tA(t) = a(1+r)^t applies when growth or decay occurs in distinct steps (e.g., annual compounding), while the continuous model A(t)=AertA(t) = Ae^{rt} describes processes that change smoothly over time without interruption.

Intuition: Discrete models count whole periods; continuous models measure infinitesimal change at every instant.

Core distinctions:

  • Discrete: Base is (1+r)(1+r) where rr is the rate per period; tt counts complete intervals
  • Continuous: Base is Euler's number e2.718e \approx 2.718; rr is the instantaneous rate; tt is any real number
  • Growth when r>0r > 0; decay when r<0r < 0 in both models
  • The relationship ert=limn(1+r/n)nte^{rt} = \lim_{n \to \infty}(1 + r/n)^{nt} bridges the two forms

Consequence: Choosing the correct model depends on whether the process updates periodically or continuously.

Example: A population growing 5% yearly uses P(t)=P0(1.05)tP(t) = P_0(1.05)^t, while bacteria dividing continuously use P(t)=P0e0.05tP(t) = P_0 e^{0.05t}.

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Level 2
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A bank account compounds interest exactly once at the end of every year. Which type of mathematical model best describes the balance over time?

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✖️ 2. Parameter interpretation: initial value and growth multiplier

🎯 Parameter Interpretation

  • In y=abty = ab^t, the parameter aa is the initial value when t=0t=0.
  • The base bb is the growth multiplier per unit time.
  • If b>1b > 1 the function shows growth, if 0<b<10 < b < 1 it shows decay.
  • In continuous form AektAe^{kt}, the constant AA is initial value and eke^k acts like bb.
  • Positive kk means growth, negative kk means decay.

For y=50(1.2)ty = 50(1.2)^t, we start at 50 and multiply by 1.2 each step, so after 2 steps: 50(1.2)2=7250(1.2)^2 = 72.

💡 aa = start, bb = multiplier per step.

2. Parameter interpretation: initial value and growth multiplier

Parameter Interpretation in Exponential Functions

In the general exponential function f(t)=abtf(t) = a \cdot b^t, the parameter aa represents the initial value (the quantity at t=0t=0), while bb is the growth multiplier determining the factor by which the quantity changes per unit time. For continuous models A(t)=AektA(t) = Ae^{kt}, the base multiplier is eke^k, equivalent to bb in discrete form.

Intuition: The initial value aa sets the starting point; the base bb controls how rapidly the function grows or shrinks.

Core rules:

  • Initial value: f(0)=ab0=af(0) = a \cdot b^0 = a always, since any nonzero base to the zero power equals 1
  • Growth multiplier: If b>1b > 1 (or k>0k > 0), exponential growth occurs; if 0<b<10 < b < 1 (or k<0k < 0), exponential decay occurs
  • Never b0b \leq 0: The base must be positive to maintain real outputs
  • The equivalence b=ekb = e^k connects discrete and continuous forms

Consequence: Identifying aa and bb immediately reveals the starting quantity and growth behavior.

Example: In f(t)=200(0.8)tf(t) = 200(0.8)^t, the initial value is 200 units, and the quantity retains 80% each period (20% decay rate).

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Level 2
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The population of a small town is modeled by the function P(t)=450(1.05)tP(t) = 450(1.05)^t, where tt is the number of years. What is the initial population of the town?

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✖️ 3. Defining the exponential domain and strict range constraint

📊 Domain and Range Constraints

  • The domain of any exponential function f(x)=abxf(x) = ab^x is all real numbers R\mathbb{R}.
  • The range is strictly positive numbers only (never zero or negative).
  • Even if aa is negative, write it as abx-|a|b^x where abx>0|a|b^x > 0 always.
  • The graph never touches the x-axis (horizontal asymptote at y=0y=0).
  • Exponentials cannot output zero because bx>0b^x > 0 for all real xx.

For f(x)=3(2)xf(x) = 3(2)^x, you can plug in x=100x = -100 or x=πx = \pi, but output is always positive: f(2)=3(2)2=0.75>0f(-2) = 3(2)^{-2} = 0.75 > 0.

💡 Input = anything, Output = always positive.

3. Defining the exponential domain and strict range constraint

Domain and Range of Exponential Functions

For any exponential function f(x)=abxf(x) = a \cdot b^x where a0a \neq 0 and b>0b > 0, b1b \neq 1, the domain is all real numbers R\mathbb{R}, meaning the exponent can be any value. The range is strictly constrained: if a>0a > 0, then f(x)>0f(x) > 0 for all xx; if a<0a < 0, then f(x)<0f(x) < 0 for all xx. The function never equals zero.

Intuition: You can raise a positive base to any power, but the output's sign matches the coefficient aa and never crosses zero.

Core rules:

  • Domain: xRx \in \mathbb{R} (no restrictions on input)
  • Range when a>0a > 0: f(x)(0,)f(x) \in (0, \infty) exclusively
  • Range when a<0a < 0: f(x)(,0)f(x) \in (-\infty, 0) exclusively
  • Zero is never achieved: bx>0b^x > 0 for all real xx when b>0b > 0

Consequence: Exponential functions model quantities that remain positive (like populations) or negative (like debt growing in magnitude) but cannot change sign.

Example: For f(x)=3(2)xf(x) = 3(2)^x, domain is all reals, range is (0,)(0, \infty); f(x)f(x) approaches 0 as xx \to -\infty but never reaches it.

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What is the range of the exponential function f(x)=8(1.5)xf(x) = 8 * (1.5)^x?

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✖️ 4. Graphing exponential functions and tracking the horizontal asymptote through transformations

📈 Graphing and Horizontal Asymptotes

  • The basic graph y=bxy = b^x has a horizontal asymptote at y=0y = 0.
  • Transforming to y=abxc+dy = ab^{x-c} + d shifts the asymptote to y=dy = d.
  • The parameter cc shifts the graph horizontally (right if c>0c > 0).
  • The parameter dd shifts the graph vertically and moves the asymptote.
  • Growth functions rise to infinity, decay functions approach the asymptote from above.

For y=2(3)x1+5y = 2(3)^{x-1} + 5, the asymptote moves from y=0y=0 to y=5y=5, and the graph shifts right 1 unit.

💡 Asymptote = the dd value, graph never crosses it.

4. Graphing exponential functions and tracking the horizontal asymptote through transformations

Graphing and Horizontal Asymptotes in Transformed Exponentials

The general transformed exponential f(x)=abxc+df(x) = a \cdot b^{x-c} + d shifts the basic graph horizontally by cc, vertically by dd, and scales by aa. The horizontal asymptote moves from y=0y=0 (for abxab^x) to y=dy=d after vertical translation. This asymptote represents the limiting value as xx \to \infty (if 0<b<10 < b < 1) or xx \to -\infty (if b>1b > 1).

Intuition: Vertical shifts relocate the asymptote; the function approaches dd but never crosses it.

Core rules:

  • Horizontal asymptote: Always y=dy = d in the form abxc+da \cdot b^{x-c} + d
  • Growth (b>1b > 1): Graph rises to the right, approaches dd from below (if a>0a > 0) as xx \to -\infty
  • Decay (0<b<10 < b < 1): Graph falls to the right, approaches dd from above (if a>0a > 0) as xx \to \infty
  • Reflection: If a<0a < 0, the graph flips across the asymptote

Consequence: Identifying dd immediately reveals the long-term behavior and asymptote location.

Example: For f(x)=2(0.5)x1+3f(x) = -2(0.5)^{x-1} + 3, the horizontal asymptote is y=3y=3; as xx \to \infty, f(x)3f(x) \to 3 from below.

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Level 2
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Find the horizontal asymptote of the function f(x)=43x2+8f(x) = -4 \cdot 3^{x-2} + 8. Enter the numerical value of dd for the asymptote y=dy = d.

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✖️ 5. Applications: Modeling population dynamics, radioactive half-life, and continuously compounded interest

🌍 Real-World Applications

  • Population growth: bacteria double every hour using P(t)=P02tP(t) = P_0 \cdot 2^t.
  • Radioactive decay: half-life formula N(t)=N0(0.5)t/hN(t) = N_0(0.5)^{t/h} where hh is half-life period.
  • Compound interest: continuous compounding uses A=PertA = Pe^{rt} where rr is annual rate.
  • Discrete compounding uses A=P(1+r/n)ntA = P(1 + r/n)^{nt} for nn periods per year.
  • All three contexts use the same exponential structure with different interpretations.

A sample of 100g decays with half-life 10 years: after 20 years, N(20)=100(0.5)20/10=25N(20) = 100(0.5)^{20/10} = 25 grams remain.

💡 Growth doubles, decay halves, interest compounds.

5. Applications: Modeling population dynamics, radioactive half-life, and continuously compounded interest

Real-World Applications of Exponential Models

Exponential functions model three critical phenomena: population growth in biology (where organisms reproduce proportionally to current population), radioactive decay in physics (where unstable atoms decay at a constant rate), and compound interest in finance (where investments grow based on accumulated value).

Intuition: Whenever a rate of change is proportional to the current amount, exponential behavior emerges.

Core applications:

  • Population dynamics: P(t)=P0ertP(t) = P_0 e^{rt} where rr is the per capita growth rate; models bacteria, wildlife, or human populations under ideal conditions
  • Radioactive half-life: N(t)=N0(0.5)t/hN(t) = N_0 (0.5)^{t/h} where hh is the half-life period; describes decay of isotopes like Carbon-14 or Uranium-235
  • Continuous compounding: A(t)=PertA(t) = Pe^{rt} where PP is principal, rr is annual rate; maximizes growth compared to periodic compounding
  • Common constraint: All three assume constant rates and no external interference

Consequence: Exponential models provide precise predictions when growth or decay rates remain proportional to quantity.

Example: An investment of 5000 dollars at 4% continuous annual interest grows to A(10)=5000e0.04(10)7459A(10) = 5000e^{0.04(10)} \approx 7459 dollars after 10 years.

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According to the theory, which formula is specifically used to describe the decay of isotopes like Carbon-14?

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