Graphs of sine and cosine (amplitude, period, phase shift)

LVL: FREE

MODULE: Trigonometric Functions and Identities

[EXEC: MICRO_CORE]

âœ–ī¸ 1. Anatomy of the basic graphs: domain, range, midline, and key points (zeros, max, min)

📊 Basic Sine and Cosine Anatomy

  • Domain is all real numbers (the wave goes on forever).
  • Range is [-1, 1] for both y=sin⁥(x)y = \sin(x) and y=cos⁥(x)y = \cos(x).
  • Midline is the horizontal line y=0y = 0 (the center of oscillation).
  • Sine zeros occur at x=0,Ī€,2Ī€,3Ī€,â€Ļx = 0, \pi, 2\pi, 3\pi, \ldots (multiples of Ī€\pi).
  • Cosine starts at max (1 at x=0x = 0), sine starts at midline (0 at x=0x = 0).
  • Period is 2Ī€2\pi (the wave repeats every 2Ī€2\pi units).

For y=sin⁥(x)y = \sin(x): at x=0x = 0 the value is 0, at x=Ī€/2x = \pi/2 the value is 1, at x=Ī€x = \pi the value is 0.

💡 Sine starts at zero going up, cosine starts at the top.

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1. Anatomy of the basic graphs: domain, range, midline, and key points (zeros, max, min)

Anatomy of the Basic Graphs

The functions y=sin⁡(x)y = \sin(x) and y=cos⁡(x)y = \cos(x) are periodic waves with domain (−∞,∞)(-\infty, \infty) and range [−1,1][-1, 1]. The midline is the horizontal line y=0y = 0 that bisects the graph, representing the average value of the function.

Both functions oscillate symmetrically about their midline, creating a predictable wave pattern.

Core structural features:

  • Period: Both complete one full cycle over an interval of length 2Ī€2\pi
  • Zeros of sine: x=nĪ€x = n\pi for any integer nn; zeros of cosine: x=Ī€2+nĪ€x = \frac{\pi}{2} + n\pi
  • Maximum value: 11 occurs at x=Ī€2+2nĪ€x = \frac{\pi}{2} + 2n\pi for sine, x=2nĪ€x = 2n\pi for cosine
  • Minimum value: −1-1 occurs at x=3Ī€2+2nĪ€x = \frac{3\pi}{2} + 2n\pi for sine, x=Ī€+2nĪ€x = \pi + 2n\pi for cosine

These key points divide each period into four equal quarters of length ΀2\frac{\pi}{2}, creating the characteristic wave shape.

Example: For y=sin⁥(x)y = \sin(x) on [0,2Ī€][0, 2\pi], zeros occur at 0,Ī€,2Ī€0, \pi, 2\pi; maximum at Ī€2\frac{\pi}{2}; minimum at 3Ī€2\frac{3\pi}{2}.

TASK_1[0 / 3]
LVL_2
RSN: PATTERN

The function y=sin⁥(x)y = \sin(x) oscillates symmetrically about its midline y=0y = 0. Based on its range, what is the maximum value this function can reach?

DEEP_COMPUTE
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[EXEC: MICRO_CORE]

âœ–ī¸ 2. Calculating and graphing amplitude changes (âˆŖaâˆŖ|a|) and reflections (handling negative amplitude)

đŸŽĸ Amplitude Changes and Flips

  • Amplitude is âˆŖaâˆŖ|a| in y=asin⁥(x)y = a\sin(x) or y=acos⁥(x)y = a\cos(x) (vertical stretch).
  • The new range becomes [âˆ’âˆŖaâˆŖ,âˆŖaâˆŖ][-|a|, |a|] (wave height doubles from midline).
  • If aa is negative, the graph flips upside down (reflection over midline).
  • Amplitude does NOT change the period or horizontal spacing.
  • To find max height, calculate âˆŖaâˆŖ|a| above and below the midline.

For y=3sin⁥(x)y = 3\sin(x): amplitude is 3, range is [-3, 3], max at Ī€/2\pi/2 is 3.

💡 Amplitude = how tall the wave is, negative flips it.

[EXEC: DEEP_COMPUTE]

2. Calculating and graphing amplitude changes (âˆŖaâˆŖ|a|) and reflections (handling negative amplitude)

Amplitude Changes and Reflections

For y=asin⁥(x)y = a\sin(x) or y=acos⁥(x)y = a\cos(x), the amplitude is âˆŖaâˆŖ|a|, representing the maximum distance from the midline to a peak or trough. This stretches or compresses the graph vertically without affecting the period.

Amplitude determines the range: [âˆ’âˆŖaâˆŖ,âˆŖaâˆŖ][-|a|, |a|] when the midline is y=0y = 0.

Core rules for coefficient aa:

  • If âˆŖaâˆŖ>1|a| > 1: vertical stretch (taller waves)
  • If 0<âˆŖaâˆŖ<10 < |a| < 1: vertical compression (flatter waves)
  • If a<0a < 0: reflection across the xx-axis occurs in addition to the amplitude change
  • The midline and period remain unchanged by amplitude transformations

When aa is negative, every output value is negated, flipping peaks to troughs and vice versa.

Example: For y=−3sin⁥(x)y = -3\sin(x), amplitude is âˆŖâˆ’3âˆŖ=3|{-3}| = 3, range is [−3,3][-3, 3], and the graph is reflected so the first quarter-period descends from 00 to −3-3 instead of ascending to 33.

TASK_1[0 / 3]
LVL_2
RSN: PATTERN

Find the amplitude of the function y=−5cos⁡(x)y = -5\cos(x).

DEEP_COMPUTE
ULTRA
[EXEC: MICRO_CORE]

âœ–ī¸ 3. Calculating and graphing period changes (2Ī€/b2\pi/b) and handling negative inside coefficients

âąī¸ Period Changes and Inside Negatives

  • Period formula is 2Ī€âˆŖbâˆŖ\frac{2\pi}{|b|} for y=sin⁥(bx)y = \sin(bx) or y=cos⁥(bx)y = \cos(bx).
  • Larger âˆŖbâˆŖ|b| makes the wave compress horizontally (faster oscillation).
  • Smaller âˆŖbâˆŖ|b| makes the wave stretch horizontally (slower oscillation).
  • If bb is negative, factor it out as sin⁥(−bx)=−sin⁥(bx)\sin(-bx) = -\sin(bx) (creates vertical flip).
  • Always use âˆŖbâˆŖ|b| in the period formula, then handle the negative separately.

For y=sin⁥(2x)y = \sin(2x): period is 2Ī€/2=Ī€2\pi/2 = \pi, the wave completes one cycle in Ī€\pi units.

💡 Period = how long before the wave repeats, use absolute value of b.

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3. Calculating and graphing period changes (2Ī€/b2\pi/b) and handling negative inside coefficients

Period Changes and Inside Coefficients

For y=sin⁥(bx)y = \sin(bx) or y=cos⁥(bx)y = \cos(bx), the period is 2Ī€âˆŖbâˆŖ\frac{2\pi}{|b|}, representing the horizontal length of one complete cycle. The coefficient bb compresses or stretches the graph horizontally.

The period formula uses âˆŖbâˆŖ|b| because negative values of bb affect symmetry, not period length.

Core rules for coefficient bb:

  • If âˆŖbâˆŖ>1|b| > 1: horizontal compression (more cycles in 2Ī€2\pi)
  • If 0<âˆŖbâˆŖ<10 < |b| < 1: horizontal stretch (fewer cycles in 2Ī€2\pi)
  • If b<0b < 0: for sine, this reflects the graph across the yy-axis; for cosine, no visible change occurs due to even symmetry
  • Key points are spaced at intervals of period4=Ī€2âˆŖbâˆŖ\frac{\text{period}}{4} = \frac{\pi}{2|b|}

Always compute period using the absolute value to avoid negative lengths.

Example: For y=cos⁥(3x)y = \cos(3x), period is 2Ī€3\frac{2\pi}{3}, so three complete cycles fit in [0,2Ī€][0, 2\pi], with key points at 0,Ī€6,Ī€3,Ī€2,â€Ļ0, \frac{\pi}{6}, \frac{\pi}{3}, \frac{\pi}{2}, \ldots

TASK_1[0 / 3]
LVL_2
RSN: PATTERN

Find the period of the function y=sin⁥(4x)y = \sin(4x).

DEEP_COMPUTE
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[EXEC: MICRO_CORE]

âœ–ī¸ 4. Combining transformations including phase shifts (−c/b-c/b) and vertical translations (dd)

🔄 Full Transformation Formula

  • General form is y=asin⁥(b(x−c))+dy = a\sin(b(x - c)) + d or y=acos⁥(b(x−c))+dy = a\cos(b(x - c)) + d.
  • Phase shift is cc (horizontal shift right if positive, left if negative).
  • Vertical shift is dd (moves the midline up or down to y=dy = d).
  • Calculate phase shift as −c/b-c/b when written as y=asin⁥(bx+c)y = a\sin(bx + c).
  • New range becomes [dâˆ’âˆŖaâˆŖ,d+âˆŖaâˆŖ][d - |a|, d + |a|] after all transformations.
  • Apply transformations in order: horizontal stretch, shift, vertical stretch, shift.

For y=2sin⁥(3(xâˆ’Ī€/4))+1y = 2\sin(3(x - \pi/4)) + 1: amplitude 2, period 2Ī€/32\pi/3, shift right Ī€/4\pi/4, midline at y=1y = 1.

💡 Phase shift moves the wave left or right, d moves the midline up or down.

[EXEC: DEEP_COMPUTE]

4. Combining transformations including phase shifts (−c/b-c/b) and vertical translations (dd)

Combining Multiple Transformations

The general form y=asin⁥(b(x−c))+dy = a\sin(b(x - c)) + d or y=acos⁥(b(x−c))+dy = a\cos(b(x - c)) + d combines four transformations: amplitude âˆŖaâˆŖ|a|, period 2Ī€âˆŖbâˆŖ\frac{2\pi}{|b|}, phase shift cc (horizontal translation), and vertical shift dd (midline translation). When written as y=asin⁥(bx−c)+dy = a\sin(bx - c) + d, the phase shift is cb\frac{c}{b}.

The midline becomes y=dy = d, and the range shifts to [dâˆ’âˆŖaâˆŖ,d+âˆŖaâˆŖ][d - |a|, d + |a|].

Transformation order (applied to parent function):

  • Horizontal: Apply phase shift cc units right (if c>0c > 0) or left (if c<0c < 0)
  • Horizontal: Apply period change via factor bb
  • Vertical: Apply amplitude scaling âˆŖaâˆŖ|a| and reflection if a<0a < 0
  • Vertical: Apply vertical shift dd to move the midline

Always extract bb as a factor before identifying the phase shift to avoid errors.

Example: For y=2sin⁥(3xâˆ’Ī€)+1y = 2\sin(3x - \pi) + 1, rewrite as y=2sin⁥(3(xâˆ’Ī€3))+1y = 2\sin(3(x - \frac{\pi}{3})) + 1: amplitude 22, period 2Ī€3\frac{2\pi}{3}, phase shift Ī€3\frac{\pi}{3} right, midline y=1y = 1, range [−1,3][-1, 3].

TASK_1[0 / 3]
LVL_3
RSN: PATTERN

Given the function y=−3cos⁥[2xâˆ’Ī€]+4y = -3\cos[2x - \pi] + 4, what is the range of the function?

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âœ–ī¸ 5. Applications: Modeling sound waves in acoustics, spring-mass systems, and pendulum oscillations

đŸŽĩ Real-World Wave Applications

  • Sound waves use y=asin⁥(bt)y = a\sin(bt) where amplitude is volume and period relates to pitch.
  • Higher frequency (smaller period) means higher pitched sound.
  • Spring-mass systems model vertical position as y=acos⁥(bt)+dy = a\cos(bt) + d where dd is equilibrium.
  • Pendulum angle follows θ=asin⁥(bt)\theta = a\sin(bt) where amplitude is max swing angle.
  • Period of spring or pendulum depends on physical properties (mass, length, gravity).
  • Phase shift represents the starting position at time t=0t = 0.

A tuning fork at 440 Hz vibrates with y=0.01sin⁥(880Ī€t)y = 0.01\sin(880\pi t) where period is 1/4401/440 seconds.

💡 Sine and cosine model anything that oscillates back and forth regularly.

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5. Applications: Modeling sound waves in acoustics, spring-mass systems, and pendulum oscillations

Applications in Physical Systems

Sine and cosine functions model periodic phenomena where quantities oscillate regularly over time. In acoustics, sound waves are modeled as y=asin⁥(2Ī€ft)y = a\sin(2\pi ft) where aa is amplitude (loudness), ff is frequency in hertz, and period 1f\frac{1}{f} represents the time for one cycle.

These models capture the repetitive nature of oscillatory motion in physical systems.

Key application domains:

  • Sound waves: Amplitude corresponds to volume; frequency to pitch; a 440 Hz tone (musical A) has period 1440\frac{1}{440} seconds
  • Spring-mass systems: Displacement x(t)=acos⁥(Ήt+Ī•)x(t) = a\cos(\omega t + \phi) where Ή=k/m\omega = \sqrt{k/m} depends on spring constant kk and mass mm
  • Pendulum motion: Angular displacement θ(t)=θ0cos⁥(g/L⋅t)\theta(t) = \theta_0\cos(\sqrt{g/L} \cdot t) for small angles, where gg is gravity and LL is length
  • Phase shift Ī•\phi represents initial conditions (starting position)

Example: A spring with mass 2 kg and constant 50 N/m oscillates as x(t)=0.1cos⁥(5t)x(t) = 0.1\cos(5t) meters, with amplitude 0.1 m and period 2Ī€5\frac{2\pi}{5} seconds.

TASK_1[0 / 3]
LVL_2
MOD: TRANSLATE

A tuning fork produces a sound wave with a frequency of 250 Hz. What is the period of this sound wave in seconds?

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